If X + 1/X = 10 then X5
+ 1/X5 = ?
Solution :-
Trick :- Coefficient is summation of Above two
numbers
For example after squaring we get
equation like this à X2 + 2 +1/X2
Coefficients are 1 2 1
For cube coefficients can be
derived as 1 (1+2=3) (2+1=3) 1
For 4th power
coefficients can be derived as 1 (1+3=4) (3+3=6) (3+1=4) 1
|
1 |
|||||||||
|
|
|
1 |
|||||||
|
|
|
3 |
1 |
||||||
|
1 |
4 |
6 |
4 |
1 |
|||||
|
1 |
5 |
10 |
10 |
5 |
1 |
||||
|
1 |
6 |
15 |
20 |
15 |
6 |
1 |
|||
|
1 |
7 |
21 |
35 |
35 |
21 |
7 |
1 |
||
|
1 |
8 |
28 |
56 |
70 |
56 |
28 |
8 |
1 |
|
|
1 |
9 |
36 |
84 |
126 |
126 |
84 |
36 |
9 |
1 |
X + 1/X = 10 ………… (1)
Squaring on both sides
(X + 1/X)2 =
100 so X2 + 2 +1/X2 = 100 hence X2
+ 1/X2 = 98 ………(2)
Similarly
(X + 1/X)3 = 100
so X3+ 3*X2 * 1/X + 3*X * 1/X2 +1/X3
= 1000
Therefore, X3+ 3X + 3/X +1/X3 = 1000
X3+1/X3
+3(X+1/X) = 1000
X3+1/X3
+3(10) = 1000
X3+1/X3
= 970 ……………(3)
Now
if You closely observed even powers terms are missing as they are missing which
means we don’t need to worry about calculating value of X4+1/X4
for X5+1/X5 so we directly jump on 5th power
equation.
(X + 1/X)5 = 105
X5+ 5*X4 *
1/X + 10*X3 * 1/X2 + 10*X2 * 1/X3 +
5*X * 1/X4 +1/X5 = 100000
X5+ 5X3 + 10X
+ 10/X + 5/X3 +1/X5 = 100000
X5+ 1/X5 + 5X3
+ 5/X3 + 10X + 10/X
= 100000
X5+ 1/X5 + 5(X3
+ 1/X3) + 10(X + 1/X) = 100000
X5+ 1/X5 + 5(970)
+ 10(10) = 100000 ……… from equation 1
and 3
X5+ 1/X5 =
95050.
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